Solve ∣cos⁡x−2sin⁡2x−cos⁡3x∣=1−2sin⁡x−cos⁡2x.|\cos x - 2 \sin 2x - \cos 3x| = 1 - 2 \sin x - \cos 2x.

Problem

Solve ∣cos⁡x−2sin⁡2x−cos⁡3x∣=1−2sin⁡x−cos⁡2x.|\cos x - 2 \sin 2x - \cos 3x| = 1 - 2 \sin x - \cos 2x.

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