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Mathematics
Problem
If
7
x
+
3
y
+
9
=
0
7x + 3y + 9 = 0
7
x
+
3
y
+
9
=
0
and
y
=
k
x
+
7
y = kx + 7
y
=
k
x
+
7
are two perpendicular lines then
k
k
k
is :- (1)
3
/
7
3/7
3/7
(2)
−
7
/
3
-7/3
−
7/3
(3) 3 (4) 7
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