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Mathematics
Mathematics
Problem
The velocity of a particle is
v
(
t
)
=
⟨
6
t
−
10
,
t
2
−
9
⟩
\mathbf v(t)=\langle 6t-10,\;t^{2}-9\rangle
v
(
t
)
=
⟨
6
t
−
10
,
t
2
−
9
⟩
for
0
≤
t
≤
6
0\le t\le6
0
≤
t
≤
6
. Determine every time in this interval at which the particle changes horizontal direction.
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