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Mathematics
Mathematics
Problem
Find
d
d
x
[
(
3
x
2
+
1
)
sin
x
]
\dfrac{d}{dx}\big[(3x^{2}+1)\sin x\big]
d
x
d
[
(
3
x
2
+
1
)
sin
x
]
. a)
(
3
x
2
+
1
+
6
x
)
cos
x
(3x^{2}+1+6x)\cos x
(
3
x
2
+
1
+
6
x
)
cos
x
b)
(
3
x
2
+
1
)
sin
x
+
6
x
cos
x
(3x^{2}+1)\sin x + 6x\cos x
(
3
x
2
+
1
)
sin
x
+
6
x
cos
x
c)
(
3
x
2
+
1
)
cos
x
+
6
x
sin
x
(3x^{2}+1)\cos x + 6x\sin x
(
3
x
2
+
1
)
cos
x
+
6
x
sin
x
d)
(
3
x
2
+
1
)
cos
x
−
6
x
sin
x
(3x^{2}+1)\cos x - 6x\sin x
(
3
x
2
+
1
)
cos
x
−
6
x
sin
x
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