Physics

Problem

A particle moves along the

x

-axis from

x=0

x=6\,\text{m}

. The force acting on it is defined as follows: • For

0 \le x \le 3\,\text{m}

F = 6\,\text{N}

. • For

3 \le x \le 6\,\text{m}

F(x)=6-2(x-3)\,\text{N}

. The total work done on the particle during the

6\,\text{m}

displacement is a)

36\,\text{J}

18\,\text{J}

27\,\text{J}

24\,\text{J}