Problem

Problem

Statement I If in a triangle ABC sin⁡2A+sin⁡2B+sin⁡2C=2\sin^2 A + \sin^2 B + \sin^2 C = 2 , then one of the angles must be 90∘90^\circ . Statement II In any triangles ABC cos⁡2A+cos⁡2B+cos⁡2C=−1−4cos⁡Acos⁡Bcos⁡C\cos 2A + \cos 2B + \cos 2C = -1 - 4 \cos A \cos B \cos C

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