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Mathematics
Mathematics
Problem
If
f
:
[
−
1
,
1
]
→
[
−
1
2
,
1
2
]
f: [-1, 1] \to \left[-\frac{1}{2}, \frac{1}{2}\right]
f
:
[
−
1
,
1
]
→
[
−
2
1
,
2
1
]
,
f
(
x
)
=
x
1
+
x
2
f(x) = \frac{x}{1+x^2}
f
(
x
)
=
1
+
x
2
x
. The area bounded by
y
=
f
−
1
(
x
)
y = f^{-1}(x)
y
=
f
−
1
(
x
)
,
X
X
X
-axis,
x
=
1
2
x = \frac{1}{2}
x
=
2
1
,
x
=
−
1
2
x = -\frac{1}{2}
x
=
−
2
1
is a.
1
2
log
e
\frac{1}{2} \log e
2
1
lo
g
e
b.
log
(
e
2
)
\log\left(\frac{e}{2}\right)
lo
g
(
2
e
)
c.
1
2
log
e
3
\frac{1}{2} \log \frac{e}{3}
2
1
lo
g
3
e
d.
1
2
log
(
e
2
)
\frac{1}{2} \log\left(\frac{e}{2}\right)
2
1
lo
g
(
2
e
)
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