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Mathematics
Mathematics
Problem
Prove that
sin
2
(
90
∘
−
θ
)
+
cos
2
(
90
∘
−
θ
)
=
1
\sin^{2}(90^\circ - \theta) + \cos^{2}(90^\circ - \theta) = 1
sin
2
(
9
0
∘
−
θ
)
+
cos
2
(
9
0
∘
−
θ
)
=
1
for any acute angle
θ
\theta
θ
.
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