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Mathematics
Problem
Choose the sigma notation equivalent to the alternating series
1
−
2
+
3
−
4
+
5
−
6
1 - 2 + 3 - 4 + 5 - 6
1
−
2
+
3
−
4
+
5
−
6
. a)
∑
k
=
1
6
(
−
1
)
k
k
\displaystyle\sum_{k=1}^{6} (-1)^{k} k
k
=
1
∑
6
(
−
1
)
k
k
b)
∑
k
=
0
5
(
−
1
)
k
+
1
(
k
+
1
)
\displaystyle\sum_{k=0}^{5} (-1)^{k+1} (k+1)
k
=
0
∑
5
(
−
1
)
k
+
1
(
k
+
1
)
c)
∑
k
=
1
6
(
−
1
)
k
+
1
k
\displaystyle\sum_{k=1}^{6} (-1)^{k+1} k
k
=
1
∑
6
(
−
1
)
k
+
1
k
d)
∑
k
=
1
5
(
−
1
)
k
+
1
k
\displaystyle\sum_{k=1}^{5} (-1)^{k+1} k
k
=
1
∑
5
(
−
1
)
k
+
1
k
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