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Mathematics
Problem
The sum of the real roots of the equation
∣
x
−
6
−
1
2
−
3
x
x
−
3
−
3
2
x
x
+
2
∣
=
0
\begin{vmatrix} x & -6 & -1 \\ 2 & -3x & x-3 \\ -3 & 2x & x+2 \end{vmatrix} = 0
x
2
−
3
−
6
−
3
x
2
x
−
1
x
−
3
x
+
2
=
0
, is equal to: [JEE-MAIN ONLINE-2019] (1) 6 (2) 1 (3) 0 (4) -4
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