Physics

Physics

Problem

A ray of light comes along the line L=0L = 0 and strikes the plane mirror kept along the plane P=0P = 0 at BB . A(2,1,6)A(2, 1, 6) is a point on the line L=0L = 0 whose image about P=0P = 0 is A′A' . It is given that L=0L = 0 is x−23=y−14=z−65\frac{x-2}{3} = \frac{y-1}{4} = \frac{z-6}{5} and P=0P = 0 is x+y−2z=3x + y - 2z = 3 . If L1=0L_1 = 0 is the reflected ray, then its equation is a. \frac{x+10}{4} = \frac{y-5}{4} = \frac{z+2}{3} b. \frac{x+10}{3} = \frac{y+15}{5} = \frac{z+14}{5} c. \frac{x+10}{4} = \frac{y+15}{5} = \frac{z+14}{3} d. None of the above

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