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Mathematics
Mathematics
Problem
The normal at the point
(
3
,
4
)
(3, 4)
(
3
,
4
)
on a circle cuts the circle at the point
(
−
1
,
−
2
)
(-1, -2)
(
−
1
,
−
2
)
. Then, the equation of the circle is a.
x
2
+
y
2
+
2
x
−
2
y
−
13
=
0
x^2 + y^2 + 2x - 2y - 13 = 0
x
2
+
y
2
+
2
x
−
2
y
−
13
=
0
b.
x
2
+
y
2
−
2
x
−
2
y
−
11
=
0
x^2 + y^2 - 2x - 2y - 11 = 0
x
2
+
y
2
−
2
x
−
2
y
−
11
=
0
c.
x
2
+
y
2
−
2
x
+
2
y
+
12
=
0
x^2 + y^2 - 2x + 2y + 12 = 0
x
2
+
y
2
−
2
x
+
2
y
+
12
=
0
d.
x
2
+
y
2
−
2
x
−
2
y
+
14
=
0
x^2 + y^2 - 2x - 2y + 14 = 0
x
2
+
y
2
−
2
x
−
2
y
+
14
=
0
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