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Chemistry
Chemistry
Problem
Ethylenediamine
NH
2
C
2
H
4
NH
2
\text{NH}_2\text{C}_2\text{H}_4\text{NH}_2
NH
2
C
2
H
4
NH
2
a base (B) can add 1 or 2 protons. The successive
p
K
b
pK_b
p
K
b
values are 4 and 7 respectively. The
p
[
BH
2
2
+
]
p[\text{BH}_2^{2+}]
p
[
BH
2
2
+
]
in 0.001M solution of ethylenediamine is.....
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