Physics

Problem

For a certain metal, a graph of stopping potential

V_0

versus frequency

\nu

yields a straight line with slope

4.14\times10^{-15}\,\text{V s}

. Taking

e=1.6\times10^{-19}\,\text{C}

, calculate Planck’s constant

h

. a)

4.14\times10^{-34}\,\text{J s}

6.63\times10^{-34}\,\text{J s}

1.04\times10^{-33}\,\text{J s}

6.63\times10^{-35}\,\text{J s}