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Problem If the function f ( x ) = { ( e − x + x 2 − a − x ) − 1 x , − 1 ≤ x < 0 e 1 x + e 2 x + e 3 x a e 2 x + b e 3 x , 0 < x ≤ 1 f(x)=\begin{cases}\left(\frac{e^{-x}+x^2-a}{-x}\right)^{\frac{-1}{x}}, & -1\leq x<0\\ \frac{e^{\frac{1}{x}}+e^{\frac{2}{x}}+e^{\frac{3}{x}}}{ae^{\frac{2}{x}}+be^{\frac{3}{x}}}, & 0<x\leq 1\end{cases} f ( x ) = ⎩ ⎨ ⎧ ( − x e − x + x 2 − a ) x − 1 , a e x 2 + b e x 3 e x 1 + e x 2 + e x 3 , − 1 ≤ x < 0 0 < x ≤ 1 is continuous at x = 0 x=0 x = 0 , then
(a) a = 1 , b = e 3 / 2 a=1, b=e^{3/2} a = 1 , b = e 3/2
(b) a = 1 , b = e − 3 / 2 a=1, b=e^{-3/2} a = 1 , b = e − 3/2
(c) a = 1 , b = e 1 / 2 a=1, b=e^{1/2} a = 1 , b = e 1/2
(d) a = 1 , b = e − 1 / 2 a=1, b=e^{-1/2} a = 1 , b = e − 1/2
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