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Mathematics
Mathematics
Problem
Let
d
y
d
x
=
(
y
2
+
1
)
e
x
\dfrac{dy}{dx}=(y^{2}+1)e^{x}
d
x
d
y
=
(
y
2
+
1
)
e
x
with
y
(
0
)
=
0
y(0)=0
y
(
0
)
=
0
. Which of the following gives
y
y
y
explicitly as a function of
x
x
x
? a)
y
=
tan
(
e
x
+
1
)
y=\tan\bigl(e^{x}+1\bigr)
y
=
tan
(
e
x
+
1
)
b)
y
=
tan
(
e
x
)
y=\tan\bigl(e^{x}\bigr)
y
=
tan
(
e
x
)
c)
y
=
tan
(
e
x
−
1
)
y=\tan\bigl(e^{x}-1\bigr)
y
=
tan
(
e
x
−
1
)
d)
y
=
arctan
(
e
x
−
1
)
y=\arctan\bigl(e^{x}-1\bigr)
y
=
arctan
(
e
x
−
1
)
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