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Mathematics
Mathematics
Problem
Prove that
sec
x
−
tan
x
sec
x
+
tan
x
=
1
−
sin
x
1
+
sin
x
\displaystyle \frac{\sec x-\tan x}{\sec x+\tan x}=\frac{1-\sin x}{1+\sin x}
sec
x
+
tan
x
sec
x
−
tan
x
=
1
+
sin
x
1
−
sin
x
.
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