Supersymmetry in Elementary Particle Physics · Problem 2.9

Formalism of Supersymmetry

Physics — Particle Physics · superspace-integration-formula

Problem

Using the superspace integration rules ∫d2θ 1=∫d2θ θα=0,∫d2θ (θTcθ)=1,\int d^2\theta\, 1 = \int d^2\theta\, \theta_\alpha = 0, \qquad \int d^2\theta\,(\theta^T c\theta) = 1, and the chiral superfield expansion Φ(x,θ)=ϕ(x)+2θTcψ(x)+θTcθ F(x)\Phi(x,\theta) = \phi(x) + \sqrt{2}\theta^T c\psi(x) + \theta^T c\theta\, F(x), verify the superspace integration formulae ∫d2θ Φ(x,θ)=F(x),∫d2θ W(Φ)=F(x)∂W∂ϕ−12ψTcψ∂2W∂2ϕ,\int d^2\theta\, \Phi(x,\theta) = F(x), \qquad \int d^2\theta\, W(\Phi) = F(x)\frac{\partial W}{\partial \phi} - \frac{1}{2}\psi^T c\psi \frac{\partial^2 W}{\partial^2 \phi}, and with somewhat more effort show that ∫d2θ∫d2θˉ Φ†Φ=∂mϕ∗∂mϕ+ψ†iσˉ⋅∂ψ+F∗F.\int d^2\theta \int d^2\bar{\theta}\, \Phi^\dagger \Phi = \partial^m\phi^*\partial_m\phi + \psi^\dagger i\bar{\sigma}\cdot\partial\psi + F^*F .

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