Chemistry

Problem

The rusting of iron takes place as follows :

2\text{H}^+ + 2e^- + 1/2\text{O}_2 \longrightarrow \text{H}_2\text{O} (\text{l})

;

E^{\circ} = +1.23 \text{ V}

\text{Fe}^{2+} + 2e^- \longrightarrow \text{Fe} (\text{s})

;

E^{\circ} = -0.44 \text{ V}

The

\Delta G^{\circ}

for the net process is : (IIT 2005) a.

-322 \text{ kJ mol}^{-1}

-161 \text{ kJ mol}^{-1}

-152 \text{ kJ mol}^{-1}

-76 \text{ kJ mol}^{-1}