If x(y+z−x)log⁡x=y(z+x−y)log⁡y=z(x+y−z)log⁡z,\text{ If } \frac{x(y+z-x)}{\log x} = \frac{y(z+x-y)}{\log y} = \frac{z(x+y-z)}{\log z},…

Problem

 If x(y+z−x)log⁡x=y(z+x−y)log⁡y=z(x+y−z)log⁡z,\text{ If } \frac{x(y+z-x)}{\log x} = \frac{y(z+x-y)}{\log y} = \frac{z(x+y-z)}{\log z}, then xyyx=zyyzx^y y^x = z^y y^z is equal to a. zxxzz^x x^z b. xzyxx^z y^x c. xyyzx^y y^z d. xxyyx^x y^y

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