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Problem If sum of the series 1 + x log ∣ 1 − sin x cos x ∣ ( 1 + sin x cos x ) 1 / 2 + x 2 log ∣ 1 − sin x cos x ∣ ( 1 + sin x cos x ) 1 / 4 + … ∞ 1 + x \log \left| \frac{1 - \sin x}{\cos x} \right| \left( \frac{1 + \sin x}{\cos x} \right)^{1/2} + x^2 \log \left| \frac{1 - \sin x}{\cos x} \right| \left( \frac{1 + \sin x}{\cos x} \right)^{1/4} + \dots \infty 1 + x log c o s x 1 − s i n x ( c o s x 1 + s i n x ) 1/2 + x 2 log c o s x 1 − s i n x ( c o s x 1 + s i n x ) 1/4 + … ∞ (wherever defined) is equal to k ( 1 − x ) ( 2 − x ) \frac{k(1-x)}{(2-x)} ( 2 − x ) k ( 1 − x ) , then k k k is equal to
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