Mathematics

Problem

The line

5x - 3y = 8\sqrt{2}

is a normal to the ellipse

\frac{x^2}{25} + \frac{y^2}{9} = 1

. If

\theta'

be eccentric angle of the foot of this normal, then

\theta'

is equal to a.

\frac{\pi}{6}

\frac{\pi}{4}

\frac{\pi}{3}

\frac{\pi}{2}