Mathematics

Mathematics

Problem

A straight conductor of length LL carrying current II is placed at right angles to a uniform magnetic field of strength BB. Which expression gives the magnitude of the force acting on the conductor? a) F=ILBcos⁡θF = I L B \cos\theta b) F=12ILB\displaystyle F = \frac{1}{2} I L B c) F=ILBF = I L B d) F=ILBsin⁡θF = I L B \sin\theta

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