Mathematics

Mathematics

Problem

∫dx4cos⁡32x−3cos⁡2x=\int \frac{dx}{4\cos^3 2x - 3\cos 2x} = (a) 13log⁡[sec⁡6x+tan⁡6x]+c\frac{1}{3}\log[\sec 6x + \tan 6x] + c (b) 16log⁡[sec⁡6x+tan⁡6x]+c\frac{1}{6}\log[\sec 6x + \tan 6x] + c (c) log⁡[sec⁡6x+tan⁡6x]+c\log[\sec 6x + \tan 6x] + c (d) None of these (a) 13log⁡[sec⁡6x+tan⁡6x]+c\frac{1}{3}\log[\sec 6x + \tan 6x] + c (b) 16log⁡[sec⁡6x+tan⁡6x]+c\frac{1}{6}\log[\sec 6x + \tan 6x] + c (c) log⁡[sec⁡6x+tan⁡6x]+c\log[\sec 6x + \tan 6x] + c (d) None of these

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