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Mathematics
Problem
If
f
(
x
)
=
∫
0
x
log
(
1
−
t
1
+
t
)
d
t
f(x) = \int_0^x \log\left(\frac{1-t}{1+t}\right) dt
f
(
x
)
=
∫
0
x
lo
g
(
1
+
t
1
−
t
)
d
t
, then discuss whether even or odd?
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