Physics

Physics

Problem

For an experiment in which gg is calculated from g=2s/t2g=2s/t^{2}, the percentage error in gg (% Δg\%\,\Delta g) in terms of the percentage errors in measuring the fall distance ss (% Δs\%\,\Delta s) and the fall time tt (% Δt\%\,\Delta t) is a) % Δg=2 % Δs+% Δt\%\,\Delta g = 2\,\%\,\Delta s + \%\,\Delta t b) % Δg=% Δs−2 % Δt\%\,\Delta g = \%\,\Delta s - 2\,\%\,\Delta t c) % Δg=% Δs+2 % Δt\%\,\Delta g = \%\,\Delta s + 2\,\%\,\Delta t d) % Δg=2(% Δs+% Δt)\%\,\Delta g = 2\bigl(\%\,\Delta s + \%\,\Delta t\bigr)

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