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Mathematics
Mathematics
Problem
Show that
sin
θ
+
sin
2
θ
=
2
sin
3
θ
2
cos
θ
2
\sin\theta+\sin2\theta=2\sin\dfrac{3\theta}{2}\,\cos\dfrac{\theta}{2}
sin
θ
+
sin
2
θ
=
2
sin
2
3
θ
cos
2
θ
.
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