Physics

Problem

The angular frequency of the damped oscillator is given by,

\omega = \sqrt{\left(\frac{k}{m} - \frac{r^2}{4m^2}\right)}

where

k

is the spring constant,

m

is the mass of the oscillator and

r

is the damping constant. If the ratio

\frac{r^2}{mk}

is 8%, the change in time period compared to the undamped oscillator is approximately as follows: [Main Online April 11, 2014] a. increases by 1% b. increases by 8% c. decreases by 1% d. decreases by 8%

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