lim⁡x→0(sin⁡2(π2−ax))sec⁡2(π2−bx)\lim_{x \rightarrow 0} \left( \sin^2 \left( \frac{\pi}{2 - ax} \right) \right)^{\sec^2 \left( \frac{\pi}{2 - bx} \right)}

Mathematics

Problem

lim⁡x→0(sin⁡2(π2−ax))sec⁡2(π2−bx)\lim_{x \rightarrow 0} \left( \sin^2 \left( \frac{\pi}{2 - ax} \right) \right)^{\sec^2 \left( \frac{\pi}{2 - bx} \right)}

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