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Mathematics
Mathematics
Problem
The curve
x
=
2
sin
t
,
y
=
2
cos
t
x=2\sin t,\;y=2\cos t
x
=
2
sin
t
,
y
=
2
cos
t
is given. Determine the equation of the normal at
t
=
π
3
t=\dfrac{\pi}{3}
t
=
3
π
. a)
3
x
−
y
−
2
=
0
\sqrt{3}x-y-2=0
3
x
−
y
−
2
=
0
b)
x
−
3
y
=
0
x-\sqrt{3}\,y=0
x
−
3
y
=
0
c)
x
+
3
y
−
2
3
=
0
x+\sqrt{3}\,y-2\sqrt{3}=0
x
+
3
y
−
2
3
=
0
d)
x
−
3
y
+
3
2
=
0
x-\sqrt{3}\,y+\dfrac{\sqrt{3}}{2}=0
x
−
3
y
+
2
3
=
0
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