Mathematics

Problem

A fish population grows according to

\dfrac{dy}{dt}=0.05\,y\,(1000-y)

, where

y

is the number of fish. Which statement correctly compares the instantaneous growth rates when

y=200

and when

y=800

? a) The instantaneous growth rate at

y=200

is less than that at

y=800

, and both rates are positive. b) The instantaneous growth rates at

y=200

and

y=800

are equal. c) The instantaneous growth rate at

y=200

is greater than that at

y=800

. d) The instantaneous growth rate at

y=200

is negative, whereas at

y=800

it is positive.