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Mathematics
Mathematics
Problem
Let
G
(
α
,
β
)
G(\alpha, \beta)
G
(
α
,
β
)
be the circumcentre of the triangle formed by the lines:
4
x
+
3
y
=
69
4x + 3y = 69
4
x
+
3
y
=
69
,
4
y
−
3
x
=
17
4y - 3x = 17
4
y
−
3
x
=
17
and
x
+
7
y
=
61
x + 7y = 61
x
+
7
y
=
61
. Then
(
α
−
β
)
2
+
α
+
β
(\alpha - \beta)^2 + \alpha + \beta
(
α
−
β
)
2
+
α
+
β
is equal to (a) 16 (b) 17 (c) 18 (d) 15
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