Mathematics

Mathematics

Problem

Find ∫ ⁣(4e2x−3sin⁡x+7x) dx\displaystyle \int\!\bigl(4e^{2x} - 3\sin x + 7x\bigr)\,dx. a) 2e2x−3cos⁡x+72x2+C2e^{2x} - 3\cos x + \dfrac{7}{2}x^{2} + C b) 4e2x+3cos⁡x+72x2+C4e^{2x} + 3\cos x + \dfrac{7}{2}x^{2} + C c) 2e2x+3cos⁡x+72x2+C2e^{2x} + 3\cos x + \dfrac{7}{2}x^{2} + C d) 2e2x+3cos⁡x+7x2+C2e^{2x} + 3\cos x + 7x^{2} + C

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