Physics

Problem

For a certain metal surface, light of frequency

8\times10^{14}\,\text{Hz}

produces a stopping potential of

1.2\,\text{V}

. Keeping the intensity the same, the frequency is increased to

9\times10^{14}\,\text{Hz}

. What is the new stopping potential (approximately)? a)

1.35\,\text{V}

2.03\,\text{V}

1.6\,\text{V}

1.2\,\text{V}