(a) Show that the momentum distribution of particles in a relativistic Boltzmannian gas, with ε=c(p2+m02c2)1/2, is given by
f(p)dp=Ce−βc(p2+m02c2)1/2p2dp,
with the normalization constant
C=m02cK2(βm0c2)β,Kv(z) being a modified Bessel function.
(b) Check that in the nonrelativistic limit (kT≪m0c2) we recover the Maxwellian distribution,
f(p)dp=(2πm0β)3/2e−βp2/2m0(4πp2dp),
while in the extreme relativistic limit (kT≫m0c2) we obtain
f(p)dp=8π(βc)3e−βpc(4πp2dp).
(c) Verify that, quite generally,
⟨pu⟩=3kT.