Mathematics

Mathematics

Problem

If the lines 3x−4y−7=03x - 4y - 7 = 0 and 2x−3y−5=02x - 3y - 5 = 0 are two diameters of a circle of area 49π49\pi square units, the equation of the circle is a. x2+y2+2x−2y−47=0x^2 + y^2 + 2x - 2y - 47 = 0 b. x2+y2+2x−2y−62=0x^2 + y^2 + 2x - 2y - 62 = 0 c. x2+y2−2x+2y−62=0x^2 + y^2 - 2x + 2y - 62 = 0 d. x2+y2−2x+2y−47=0x^2 + y^2 - 2x + 2y - 47 = 0

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