Problem

Problem

Let f(x)=ax+bf(x) = ax + b and g(x)=cx+dg(x) = cx + d , a≠0a \neq 0 , c≠0c \neq 0 . Assume a=1a = 1 , b=2b = 2 . If (f∘g)(x)=(g∘f)(x)(f \circ g)(x) = (g \circ f)(x) for all xx , what can you say about cc and dd (a) cc and dd both arbitrary (b) c=1c = 1 , dd arbitrary (c) cc arbitrary, d=1d = 1 (d) c=1c = 1 , d=1d = 1

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