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Mathematics
Mathematics
Problem
29. The maximum value of
[
x
(
x
−
1
)
+
1
]
1
3
,
0
≤
x
≤
1
[x(x-1)+1]^{\frac{1}{3}}, 0 \leq x \leq 1
[
x
(
x
−
1
)
+
1
]
3
1
,
0
≤
x
≤
1
is (A)
1
3
1
3
\frac{1}{3}^{\frac{1}{3}}
3
1
3
1
(B)
1
2
\frac{1}{2}
2
1
(C) 1 (D) 0 (A)
1
3
1
3
\frac{1}{3}^{\frac{1}{3}}
3
1
3
1
(B)
1
2
\frac{1}{2}
2
1
(C) 1 (D) 0
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