Physics

Physics

Problem

(a) Show that the sum of the perihelion distance rmin⁡r_{\min} and aphelion distance rmax⁡r_{\max} of a planet is equal to 2a2a, where aa is the semi-major axis of the orbit. (b) The Earth’s orbital eccentricity is 0.0170.017 and its mean distance from the Sun (taken equal to the semi-major axis) is 1.496×1011 m1.496\times10^{11}\,\text{m}. Calculate the difference between the aphelion and perihelion distances of the Earth in kilometres. a. Show that the sum of the perihelion distance rmin⁡r_{\min} and aphelion distance rmax⁡r_{\max} of a planet is equal to 2a2a, where aa is the semi-major axis of the orbit. b. The Earth’s orbital eccentricity is 0.0170.017 and its mean distance from the Sun (taken equal to the semi-major axis) is 1.496×1011 m1.496\times10^{11}\,\text{m}. Calculate the difference between the aphelion and perihelion distances of the Earth in kilometres.

Browse the problem library