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Mathematics
Mathematics
Problem
Let
f
(
x
)
=
{
x
2
−
9
x
+
3
,
x
≠
−
3
m
,
x
=
−
3
.
f(x)=\begin{cases}\dfrac{x^2-9}{x+3},&x\neq -3\\m,&x=-3\end{cases}.
f
(
x
)
=
⎩
⎨
⎧
x
+
3
x
2
−
9
,
m
,
x
=
−
3
x
=
−
3
.
Find the value of
m
m
m
so that
f
f
f
is continuous at
x
=
−
3
x=-3
x
=
−
3
.
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