Mathematics

Mathematics

Problem

If ey+xy=ee^y + xy = e the ordered pair (dydx,d2ydx2)\left(\frac{dy}{dx}, \frac{d^2y}{dx^2}\right) at x=0x = 0 is equal to (a) (1e,1e2)\left(\frac{1}{e}, \frac{1}{e^2}\right) (b) (1e,−1e2)\left(\frac{1}{e}, -\frac{1}{e^2}\right) (c) (−1e,−1e2)\left(-\frac{1}{e}, -\frac{1}{e^2}\right) (d) (−1e,1e2)\left(-\frac{1}{e}, \frac{1}{e^2}\right) (2022)

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