lim⁡x→∞cot⁡−1(x+1−x)sec⁡−1(2x+1x−1)\lim_{x \to \infty} \frac{\cot^{-1}(\sqrt{x+1} - \sqrt{x})}{\sec^{-1}\left(\frac{2x+1}{x-1}\right)}…

Problem

lim⁡x→∞cot⁡−1(x+1−x)sec⁡−1(2x+1x−1)\lim_{x \to \infty} \frac{\cot^{-1}(\sqrt{x+1} - \sqrt{x})}{\sec^{-1}\left(\frac{2x+1}{x-1}\right)} is equal to

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