Mathematics

Mathematics

Problem

The solution of the differential equation, dydx=(x−y)2\frac{dy}{dx} = (x - y)^2, when y(1)=1y(1) = 1, is : [JEE-MAIN ONLINE-2019] (1) log⁡e∣2−y2−x∣=2(y−1)\log_e \left| \frac{2-y}{2-x} \right| = 2(y-1) (2) log⁡e∣2−x2−y∣=x−y\log_e \left| \frac{2-x}{2-y} \right| = x-y (3) −log⁡e∣1+x−y1−x+y∣=x+y−2-\log_e \left| \frac{1+x-y}{1-x+y} \right| = x+y-2 (4) −log⁡e∣1−x+y1+x−y∣=2(x−1)-\log_e \left| \frac{1-x+y}{1+x-y} \right| = 2(x-1)

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