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Mathematics
Mathematics
Problem
The function
k
k
k
is defined on
[
−
3
,
6
]
[-3,6]
[
−
3
,
6
]
by
k
(
x
)
=
{
x
2
+
3
x
,
−
3
≤
x
≤
1
,
7
−
2
x
,
1
<
x
≤
6.
k(x)=\begin{cases}x^2+3x,&-3\le x\le 1,\\7-2x,&1<x\le 6.\end{cases}
k
(
x
)
=
{
x
2
+
3
x
,
7
−
2
x
,
−
3
≤
x
≤
1
,
1
<
x
≤
6.
In one or two sentences, explain why
x
=
1
x=1
x
=
1
must be included among the candidate points when determining the absolute extrema of
k
k
k
on the interval.
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