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Mathematics
Mathematics
Problem
Triangles
A
B
C
ABC
A
B
C
and
D
B
C
DBC
D
B
C
are drawn on the same base
B
C
BC
B
C
such that
A
B
=
D
C
AB = DC
A
B
=
D
C
,
A
C
=
D
B
AC = DB
A
C
=
D
B
, and
B
C
BC
B
C
is common to both triangles. If
∠
A
B
C
=
42
∘
\angle ABC = 42^{\circ}
∠
A
B
C
=
4
2
∘
, then
∠
D
C
B
\angle DCB
∠
D
C
B
is equal to a)
60
∘
60^{\circ}
6
0
∘
b)
42
∘
42^{\circ}
4
2
∘
c)
69
∘
69^{\circ}
6
9
∘
d)
48
∘
48^{\circ}
4
8
∘
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