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Mathematics
Mathematics
Problem
If
f
(
x
)
f(x)
f
(
x
)
is defined on
[
−
2
,
2
]
[-2, 2]
[
−
2
,
2
]
by
f
(
x
)
=
4
x
2
−
3
x
+
1
f(x) = 4x^2 - 3x + 1
f
(
x
)
=
4
x
2
−
3
x
+
1
and
g
(
x
)
=
f
(
−
x
)
−
f
(
x
)
x
2
+
3
g(x) = \frac{f(-x) - f(x)}{x^2 + 3}
g
(
x
)
=
x
2
+
3
f
(
−
x
)
−
f
(
x
)
, then
∫
−
2
2
g
(
x
)
d
x
=
\int_{-2}^{2} g(x)\,dx =
∫
−
2
2
g
(
x
)
d
x
=
(a) 64 (b) -48 (c) 0 (d) 24
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