Mathematics

Mathematics

Problem

Evaluate ∫01sin⁡θ(cos⁡2θ−cos⁡2π/5)(cos⁡2θ−cos⁡22π/5)sin⁡5θdθ.\int_{0}^{1} \frac{\sin \theta (\cos^2 \theta - \cos^2 \pi/5) (\cos^2 \theta - \cos^2 2\pi/5)}{\sin 5\theta} d\theta.

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