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Mathematics
Mathematics
Problem
The circle
x
2
+
y
2
−
4
x
−
8
y
+
16
=
0
x^2 + y^2 - 4x - 8y + 16 = 0
x
2
+
y
2
−
4
x
−
8
y
+
16
=
0
rolls up the tangent to it at
(
2
+
3
,
3
)
(2 + \sqrt{3}, 3)
(
2
+
3
,
3
)
by 2 units, assuming the
X
X
X
-axis as horizontal, find the equation of the circle in the new position.
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