Let f(x)=x2−12x. Using the techniques in Section 4.2, graph y=f(x). Verify that f is one-to-one on the interval (−1,1). Use the procedure outlined on Page 384 and your graphing calculator to find the formula for f−1(x). Note that since f(0)=0, it should be the case that f−1(0)=0. What goes wrong when you attempt to substitute x=0 into f−1(x)? Discuss with your classmates how this problem arose and possible remedies.