Mathematics

Mathematics

Problem

Given that x,y,zx, y, z are positive reals such that xyz=32xyz = 32. The minimum value of x2+4xy+4y2+2z2x^2 + 4xy + 4y^2 + 2z^2 is equal to: (a) 64 (b) 256 (c) 96 (d) 216

Browse the problem library